Quizsummary
0 of 150 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
 16
 17
 18
 19
 20
 21
 22
 23
 24
 25
 26
 27
 28
 29
 30
 31
 32
 33
 34
 35
 36
 37
 38
 39
 40
 41
 42
 43
 44
 45
 46
 47
 48
 49
 50
 51
 52
 53
 54
 55
 56
 57
 58
 59
 60
 61
 62
 63
 64
 65
 66
 67
 68
 69
 70
 71
 72
 73
 74
 75
 76
 77
 78
 79
 80
 81
 82
 83
 84
 85
 86
 87
 88
 89
 90
 91
 92
 93
 94
 95
 96
 97
 98
 99
 100
 101
 102
 103
 104
 105
 106
 107
 108
 109
 110
 111
 112
 113
 114
 115
 116
 117
 118
 119
 120
 121
 122
 123
 124
 125
 126
 127
 128
 129
 130
 131
 132
 133
 134
 135
 136
 137
 138
 139
 140
 141
 142
 143
 144
 145
 146
 147
 148
 149
 150
Information
Solved Questions for Mathematics Pedagogy
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 150 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Average score 

Your score 

Categories
 Not categorized 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
 16
 17
 18
 19
 20
 21
 22
 23
 24
 25
 26
 27
 28
 29
 30
 31
 32
 33
 34
 35
 36
 37
 38
 39
 40
 41
 42
 43
 44
 45
 46
 47
 48
 49
 50
 51
 52
 53
 54
 55
 56
 57
 58
 59
 60
 61
 62
 63
 64
 65
 66
 67
 68
 69
 70
 71
 72
 73
 74
 75
 76
 77
 78
 79
 80
 81
 82
 83
 84
 85
 86
 87
 88
 89
 90
 91
 92
 93
 94
 95
 96
 97
 98
 99
 100
 101
 102
 103
 104
 105
 106
 107
 108
 109
 110
 111
 112
 113
 114
 115
 116
 117
 118
 119
 120
 121
 122
 123
 124
 125
 126
 127
 128
 129
 130
 131
 132
 133
 134
 135
 136
 137
 138
 139
 140
 141
 142
 143
 144
 145
 146
 147
 148
 149
 150
 Answered
 Review

Question 1 of 150
1. Question
1 pointswhat will be 50% of a number, whose 200% is 90?
Correct
200% of x = 90 x = 45
50% of x = = 22.5
Incorrect
200% of x = 90 x = 45
50% of x = = 22.5

Question 2 of 150
2. Question
1 pointsA and B fought an election. One got 65% of the votes and won by 300 votes. Then, the total number of votes polled if no votes is invalid, is
Correct
A gets 65% of votes B gets 35% of votes as no votes are invalid.
Let total number of votes be x
Then (6535)% of x = 300
x = 1000
Incorrect
A gets 65% of votes B gets 35% of votes as no votes are invalid.
Let total number of votes be x
Then (6535)% of x = 300
x = 1000

Question 3 of 150
3. Question
1 pointsAfter deducing a commission of 10%, a music system costs Rs. 18000. Its gross value is
Correct
Gross value – 10% of gross value = Rs. 18000
90% of gross value = Rs. 18000
gross value = Rs. 20,000
Incorrect
Gross value – 10% of gross value = Rs. 18000
90% of gross value = Rs. 18000
gross value = Rs. 20,000

Question 4 of 150
4. Question
1 points90% of the population in a village is 27000. The total population of the village is
Correct
90% of population = 27000
Total population =
Incorrect
90% of population = 27000
Total population =

Question 5 of 150
5. Question
1 pointsIf 50% of a number is added to 100 the result is the number itself. Then, the number is
Correct
50% of x + 100 = x
x = 200
Incorrect
50% of x + 100 = x
x = 200

Question 6 of 150
6. Question
1 pointsA number increased by 62.5% gives 78. The number is
Correct
x + 62.5% of x = 78
x = 48
Incorrect
x + 62.5% of x = 78
x = 48

Question 7 of 150
7. Question
1 pointsA number decreased by 31% gives 552. The number is
Correct
x – 31% of x = 552
69% of x = 552
Incorrect
x – 31% of x = 552
69% of x = 552

Question 8 of 150
8. Question
1 pointsA factory produced 4000 items in a week. To fulfill the market demand the output must be increased by 23%. The number of items to be produced next week is
Correct
Incorrect

Question 9 of 150
9. Question
1 points850 labourers of a construction company were working at a particular site. The management transferred 28% of the workforce to another location. The number
of labourers now left at this site is
Correct
Incorrect

Question 10 of 150
10. Question
1 pointsOutput of a coalmine has increased from 4850 tones last year to 6305 tones this year. The percentage increase in output is
Correct
Inc% =
Incorrect
Inc% =

Question 11 of 150
11. Question
1 pointsSamuel bought two old coolers for Rs. 11000. By selling one at a profit of 24% and the other at a loss of 20%, he neither gains nor losses. The cost prices
of the dearer of the two coolers is
Correct
0.44x + 8800 = 11000
x = 5000
Incorrect
0.44x + 8800 = 11000
x = 5000

Question 12 of 150
12. Question
1 pointsA dealer sold two coolers for Rs. 3960 each. On selling one cooler he gained 10% and on selling the other he lost 10%. The dealer overall
Correct
See important fact 1 of theory
Loss % =
Incorrect
See important fact 1 of theory
Loss % =

Question 13 of 150
13. Question
1 pointsMohan bought two old scooters for Rs. 22000. By selling one at a profit of 10% and the other at a loss of 12%, he neither gains nor loses. The cost prices
of the dearer of the two scooters is
Correct
19360 + 0.22x = 22000
x = 12000
Costs of the scooters are Rs. 12000 and Rs. 10,000
Incorrect
19360 + 0.22x = 22000
x = 12000
Costs of the scooters are Rs. 12000 and Rs. 10,000

Question 14 of 150
14. Question
1 pointsThe selling price of 12 articles is the same as the cost price of 15 articles. The retailer
Correct
SP of 12 items = CP of 15 items =
SP = 15 and CP = 12
Gain % =
Incorrect
SP of 12 items = CP of 15 items =
SP = 15 and CP = 12
Gain % =

Question 15 of 150
15. Question
1 pointsThe selling price of 23 articles is the same as the cost price of 20 articles. The retailer
Correct
SP of 23 items = CP of 20 items =
SP = 20 and CP = 23
Incorrect
SP of 23 items = CP of 20 items =
SP = 20 and CP = 23

Question 16 of 150
16. Question
1 pointsThe selling price of 20 articles is the same as the cost price of 23 articles. The retailer
Correct
SP of 20 items = CP of 23 items =
SP = 23 and CP = 20
Incorrect
SP of 20 items = CP of 23 items =
SP = 23 and CP = 20

Question 17 of 150
17. Question
1 pointsThe selling price of 20 articles is the same as the cost price of 16 articles. The retailer
Correct
SP of 20 items = CP of 16 items =
Let
SP = 16; CP = 20
Loss % =
Incorrect
SP of 20 items = CP of 16 items =
Let
SP = 16; CP = 20
Loss % =

Question 18 of 150
18. Question
1 pointsA wholesaler seller 20 pens for the marked price of 15 pens to a retailer. The retailer in turn sells them at marked price. The retailer
Correct
Let MP of 1 pen be Rs. 1
CP = 15; SP = 20
Profit % =
Incorrect
Let MP of 1 pen be Rs. 1
CP = 15; SP = 20
Profit % =

Question 19 of 150
19. Question
1 pointsA defective briefcase costing Rs. 600 is being sold at a loss of 10%. If the price is further reduced by 5%, then its selling price is
Correct
SP =
=
Incorrect
SP =
=

Question 20 of 150
20. Question
1 pointsA wholesaler sells 20 pens for the marked price of 16 pens to a retailer. The retailer in turn sells them at marked price. The retailer
Correct
Let marked price of each pen be Rs. 1
CP = 16; SP = 20
Profit % =
Incorrect
Let marked price of each pen be Rs. 1
CP = 16; SP = 20
Profit % =

Question 21 of 150
21. Question
1 pointsAn article costing Rs. 840 was sold at a profit of 50%. The second purchaser sold it once again at a loss of 25%. His selling price was
Correct
SP of 2nd purchaser =
=
Incorrect
SP of 2nd purchaser =
=

Question 22 of 150
22. Question
1 pointsA machine is sold at a profit of 10%. Had it been sold for Rs. 80 less, there would have been a loss of 10%. The C.P. of the machine is
Correct
(10% + 10%) of CP = 80
20% of CP = 80
Incorrect
(10% + 10%) of CP = 80
20% of CP = 80

Question 23 of 150
23. Question
1 pointsIf an article is sold at 5% gain instead of 5% loss, the seller gets Rs.6.72 more. The C.P. of the article is
Correct
(5% + 5%) of CP = 6.72
10% of CP = 6.72
CP = Rs. 67.20
Incorrect
(5% + 5%) of CP = 6.72
10% of CP = 6.72
CP = Rs. 67.20

Question 24 of 150
24. Question
1 pointsIf by selling an article there would have been a loss of and by selling it at Rs.6 more than the earlier S.P., there would have been
a profit of 5% then the C.P. of the article is
Correct
(2.5% + 5%) of CP = 6
7.5% of CP = 6
CP =
Incorrect
(2.5% + 5%) of CP = 6
7.5% of CP = 6
CP =

Question 25 of 150
25. Question
1 pointsKishan bought a certain quantity of rice at the rate of Rs.150 per quintal and 10% of the rice was spoiled. At what price should he sell the remainder to
gain 20% of his outlay?
Correct
CP = 1 quintal = Rs. 150
Spoilage = 10% of 1 quintal = 0.1 quintal
Qty. available for sale = 0.9
Desired SP of 0.9 quintals =
SP of 1 quintal = Rs. 200
Incorrect
CP = 1 quintal = Rs. 150
Spoilage = 10% of 1 quintal = 0.1 quintal
Qty. available for sale = 0.9
Desired SP of 0.9 quintals =
SP of 1 quintal = Rs. 200

Question 26 of 150
26. Question
1 pointsList price of an audio cassette is Rs. 70. A dealer sells 4 audio cassettes for Rs. 238 after allowing discount at a certain rate. The discount allowed is
Correct
MP =
D% =
Incorrect
MP =
D% =

Question 27 of 150
27. Question
1 pointsList price of an audio cassette is Rs. 80. A dealer sells 4 audio cassettes for Rs. 272 after allowing discount a certain rate. The discount allowed is
Correct
MP =
D% =
Incorrect
MP =
D% =

Question 28 of 150
28. Question
1 pointsThe list price of an item is Rs. 2,500 and the discount series offered is 25% and 10%. Its selling price is
Correct
SP =
=
Incorrect
SP =
=

Question 29 of 150
29. Question
1 pointsThe list price of an item is Rs. 2,300 and the discount series offered is 20% and 15%. Its selling price is
Correct
SP =
=
= Rs. 1,564
Incorrect
SP =
=
= Rs. 1,564

Question 30 of 150
30. Question
1 pointsThe list of an item is Rs. 35,000 and he discount series offered is 15%, 10% and 8%. Its selling price is
Correct
SP =
=
= Rs. 24,633
Incorrect
SP =
=
= Rs. 24,633

Question 31 of 150
31. Question
1 pointsA Farmer borrowed Rs. 20,000 from a money lender at 4% per annum simple interest. The amount paid by him to clear the loan after a period of 5 years is
Correct
SI =
A = 20,000 + 4,000 = Rs. 24,000
Incorrect
SI =
A = 20,000 + 4,000 = Rs. 24,000

Question 32 of 150
32. Question
1 pointsA shopkeeper borrowed Rs. 40,000 from a financer at 3% per annum simple interest. The amount paid by him to clear the loan after a period of 2 years and 3
months is
Correct
T = 2 year 3 m =
SI =
A = 40,000 + 2,700 = Rs. 42,700
Incorrect
T = 2 year 3 m =
SI =
A = 40,000 + 2,700 = Rs. 42,700

Question 33 of 150
33. Question
1 pointsA shopkeeper borrowed Rs. 35,000 from a financer at 12% per annum simple interest. The amount paid by him to clear the loan after a period of 2 years and 6
months is
Correct
: T = 2 year 6 m =
SI =
A = 35,000 + 10,500 = Rs. 45,500
Incorrect
: T = 2 year 6 m =
SI =
A = 35,000 + 10,500 = Rs. 45,500

Question 34 of 150
34. Question
1 pointsRonnie borrowed Rs. 3,650 from a money lender at 5.5% per annum simple interest for 100 days. The amount paid by him to clear the loan at the end of the
period is (BBA 2002)
Correct
T =
SI =
A = 3,650 + 55 = Rs. 3,705
Incorrect
T =
SI =
A = 3,650 + 55 = Rs. 3,705

Question 35 of 150
35. Question
1 pointsA sum of money lent for 7 years at 7% per annum simple interest yields an interest of Rs. 2,450. The amount received is
Correct
P =
A = 5,000 + 2,450 = Rs. 7,450
Incorrect
P =
A = 5,000 + 2,450 = Rs. 7,450

Question 36 of 150
36. Question
1 pointsRonnie borrowed Rs. 7,665 from a money lender at 5.5% per annum simple interest for 120 days. The amount paid by him to clear the loan at the end of the
period is
Correct
T =
I =
= Rs. 138.6
A = 7,665 + 138.6 = Rs. 7,803.60
Incorrect
T =
I =
= Rs. 138.6
A = 7,665 + 138.6 = Rs. 7,803.60

Question 37 of 150
37. Question
1 pointsA sum of money lent for 7 years at 7% per annum simple interest yields an interest of Rs. 4,949. The amount received is
Correct
P =
A = 10,100 + 4,949 = Rs. 15,049
Incorrect
P =
A = 10,100 + 4,949 = Rs. 15,049

Question 38 of 150
38. Question
1 pointsA sum of Rs. 50,000 was borrowed for 219 days at simple interest. If Rs. 52,100 were paid to clear the loan at the end of the period then the rate of
interest is
Correct
T =
I = 52,100 – 50,000 = Rs. 2,100
r =
Incorrect
T =
I = 52,100 – 50,000 = Rs. 2,100
r =

Question 39 of 150
39. Question
1 pointsA sum of money lent at 2.5% per annum yielded a simple interest of Rs. 45,000 were paid to clear the loan then the time for which the money was borrowed is
Correct
P = 45,000 – 5,000 = Rs. 40,000
T =
Incorrect
P = 45,000 – 5,000 = Rs. 40,000
T =

Question 40 of 150
40. Question
1 pointsThe simple interest on a sum of money will be Rs. 600 after 10 years. If the principal is trebled after 5 years. What will be the total interest at the end
of the tenth year?
Correct
SI for 10 years = Rs. 600
SI for 1 year = Rs. 60
SI of for 5 years =
After 5 years principal is tripled
Hence SI for next 5 years =
Total SI for 10 years = 900 + 300 = Rs. 1,200
Incorrect
SI for 10 years = Rs. 600
SI for 1 year = Rs. 60
SI of for 5 years =
After 5 years principal is tripled
Hence SI for next 5 years =
Total SI for 10 years = 900 + 300 = Rs. 1,200

Question 41 of 150
41. Question
1 pointsA sum of money lent at 2.5% per annum yielded a simple interest of Rs. 2,500. If Rs. 42,500 were paid to clear the loan, then the time for which the money
was borrowed is
Correct
P = 42,500 – 2,500 = Rs. 40,000
T =
Incorrect
P = 42,500 – 2,500 = Rs. 40,000
T =

Question 42 of 150
42. Question
1 pointsA Farmer borrowed Rs. 24,000 at 12% per annum at simple interest from a money lender. At the end of 3 years he cleared the loan by paying Rs. 12,000 and a
gold ring. The cost of the gold ring is
Correct
I =
A = 24,000 + 8,640 = Rs. 32,640
Cost of gold ring = 32,640 – 12,000 = Rs. 20, 640
Incorrect
I =
A = 24,000 + 8,640 = Rs. 32,640
Cost of gold ring = 32,640 – 12,000 = Rs. 20, 640

Question 43 of 150
43. Question
1 pointsMr. A and Mr. B borrowed Rs. 5,600 each at % per annum simple interest for a period of years and years respectively.
The difference of the interest paid by them is
Correct
Mr. B has to pay interest for 2 years more. Hence extra interest paid
=
Incorrect
Mr. B has to pay interest for 2 years more. Hence extra interest paid
=

Question 44 of 150
44. Question
1 pointsA Farmer borrowed Rs. 25,000 at 18% per annum simple interest from a money lender. At the end of 3 years he cleared the loan by paying Rs. 30,000 and a
gold ring. The cost of the gold ring is
Correct
I =
A = 25,000 + 13,500 = Rs. 38,500
Cost of ring = 38,500 – 30,000 = Rs. 8,500
Incorrect
I =
A = 25,000 + 13,500 = Rs. 38,500
Cost of ring = 38,500 – 30,000 = Rs. 8,500

Question 45 of 150
45. Question
1 pointsMr. A and Mr. B borrowed Rs. 11,200 each at per annum simple interest for a period of years and years respectively. The difference of the interest paid by them is
Correct
Mr. B has to pay interest for 2 years more. Hence extra interest paid
=
Incorrect
Mr. B has to pay interest for 2 years more. Hence extra interest paid
=

Question 46 of 150
46. Question
1 pointsAt what rate percentage per annum simple interest will Rs. 1 produce an interest of Rs. 8 in 40 years?
Correct
SI = 8
r =
Incorrect
SI = 8
r =

Question 47 of 150
47. Question
1 pointsPrabhat took a certain amount as a loan from a bank at the rate of 8% p.a. S.I. and gave the same amount to Ashish as a loan at the rate of 12% p.a.
If at the end of 12 years, he made a profit to Rs. 3,216 in the deal, what was the original amount?Correct
Clearly profit is 4% every year
Hence of amount = Rs. 32
Incorrect
Clearly profit is 4% every year
Hence of amount = Rs. 32

Question 48 of 150
48. Question
1 pointsA man lent a certain sum of money at 7% simple interest and in 5 years the interest amounted to Rs. 650 less than the sum lent. What was the sum lent?
Correct
= P – 650
7P = 20P – 13,000
P = Rs. 1,000
Incorrect
= P – 650
7P = 20P – 13,000
P = Rs. 1,000

Question 49 of 150
49. Question
1 pointsA man borrows Rs. 1,000 on which the interest is at the rate of 5 percent and each year he pays Rs. 100 for interest and a part payment of the debt. What amount does he owe at the end of 3 years?
Correct
Interest for 1st year = 5% of 1,000 = Rs. 50
Amount paid = Rs. 100
Hence principal paid = Rs. 50
P for 2nd year = 1,000 – 50 = Rs. 950
Interest for second year = 5% of 950 = Rs. 47.50
Amount paid = Rs. 100
Hence principal paid = 100 – 47.5 = Rs. 52.5
P for 3rd year = 950 – 52.5 = Rs. 897.50
Interest for 3rd year = 5% of 897.50 = Rs. 44.875
Amount paid = Rs. 100
Hence principal paid = 100 – 44.875 = Rs. 55.125
P for 4th year = 897.5 – 55.125
= Rs. 842.375 Rs. 842.38
Incorrect
Interest for 1st year = 5% of 1,000 = Rs. 50
Amount paid = Rs. 100
Hence principal paid = Rs. 50
P for 2nd year = 1,000 – 50 = Rs. 950
Interest for second year = 5% of 950 = Rs. 47.50
Amount paid = Rs. 100
Hence principal paid = 100 – 47.5 = Rs. 52.5
P for 3rd year = 950 – 52.5 = Rs. 897.50
Interest for 3rd year = 5% of 897.50 = Rs. 44.875
Amount paid = Rs. 100
Hence principal paid = 100 – 44.875 = Rs. 55.125
P for 4th year = 897.5 – 55.125
= Rs. 842.375 Rs. 842.38

Question 50 of 150
50. Question
1 pointsI have Rs. 5,000 and I lent Rs. 2,000 at 4% and Rs. 1,500 at 5%. At what rate must I lent the remainder of the money so that my total income may be 6% of Rs. 5,000?
Correct
Interest desired =
80 + 75 + 15r = 300
Incorrect
Interest desired =
80 + 75 + 15r = 300

Question 51 of 150
51. Question
1 pointsMohan can finish a job in 60 days whereas Ram can finish the same job in 20 days. If they work together the job will be over in
Correct
time = 15 days
Incorrect
time = 15 days

Question 52 of 150
52. Question
1 pointsA can do a piece of work in 20 days and B can do it in 30 days. Time taken by them to finish the job working together is
Correct
time = 12 days
Incorrect
time = 12 days

Question 53 of 150
53. Question
1 pointsA can type 75 pages in 25 hours. A and B working together can type 135 pages in 27 hours. Time needed by B to type 42 pages is
Correct
A can type 3 pages in 1 hour
A and B can together type 5 pages in 1 hour
B can type 2 pages in an hour
B needs 21 hours to type 42 pages
Incorrect
A can type 3 pages in 1 hour
A and B can together type 5 pages in 1 hour
B can type 2 pages in an hour
B needs 21 hours to type 42 pages

Question 54 of 150
54. Question
1 pointsA and B working together can do a piece of work in 7 days. B along can do it in 8 days. After working alone on it for 5 days, B leaves the job. The work is taken over by A. The time needed by A to finish the job is
Correct
n = 21
Incorrect
n = 21

Question 55 of 150
55. Question
1 pointsX can finish a job in 12 days, Y in 18 days and Z in 9 days. If they work together the job will be over in
Correct
time = 4 days
Incorrect
time = 4 days

Question 56 of 150
56. Question
1 pointsA can dig a well in 10 days, B can dig it in 12 days and C can dig it is 15 days. If all work together the well be dug in
Correct
time = 4 days
Incorrect
time = 4 days

Question 57 of 150
57. Question
1 pointsA can do a piece of work in 5 days, B in 4 days and A, B and C in 2 days. Time needed by C to complete the job is
Correct
time = 20 days
Incorrect
time = 20 days

Question 58 of 150
58. Question
1 pointsA and B working together can mow a field in 28 days. With help of C they can finish the job in 21 days. If C works all alone the time needed by him to finish the job is
Correct
time = 84 days
Incorrect
time = 84 days

Question 59 of 150
59. Question
1 pointsA and B working together can finish a job in 2 days. If B alone can do it in 3 days then A alone can do it in
Correct
time = 6 days
Incorrect
time = 6 days

Question 60 of 150
60. Question
1 pointsA and B together can do a job in 24 days; B and C together in 18 days; and C and A together in 36 days. If they all work together the job will be over in
Correct
Adding
time = 16 days
Incorrect
Adding
time = 16 days

Question 61 of 150
61. Question
1 pointsA and B can finish a job in 12 days; B and C in 15 days and C and A in 20 days. Working alone C can finish the job in
Correct
time = 60 days
Incorrect
time = 60 days

Question 62 of 150
62. Question
1 pointsA can do a job in 24 days. B is 50% more efficient than A. Then B can finish the job in
Correct
B needs half the time
Incorrect
B needs half the time

Question 63 of 150
63. Question
1 pointsA can do twice as much work as B. If they can together finish the job in 24 days, then working alone A would have finished the job in
Correct
x = 36
Hence A requires 36 days
Incorrect
x = 36
Hence A requires 36 days

Question 64 of 150
64. Question
1 points3 men or 5 women can reap a field in 43 days. Time needed by 5 men and 6 women to do the same is
Correct
Work done by 1 man in 1 day=
Work done by 1 woman in 1 day =
Work done by 5 men and 6 women in 1 day =
Hence work will be over in 15 days.
Incorrect
Work done by 1 man in 1 day=
Work done by 1 woman in 1 day =
Work done by 5 men and 6 women in 1 day =
Hence work will be over in 15 days.

Question 65 of 150
65. Question
1 pointsIf 3 men or 4 women can do a piece of work in 43 days, then time needed by 7 men and 5 women to do the same work is
Correct
Work done by 1 man in 1 day =
Work done by 1 woman in 1 day=
Work done by 7 women and 5 women in 1 day
=
Hence work will be over in 12 days.
Incorrect
Work done by 1 man in 1 day =
Work done by 1 woman in 1 day=
Work done by 7 women and 5 women in 1 day
=
Hence work will be over in 12 days.

Question 66 of 150
66. Question
1 points30 men and 14 boys can reap a field in 121 days. If 3 men do as much work as 5 boys then 20 men and 4 boys will receipt in
Correct
…… (i)
Substituting in (i)
We get
Work done by 20 men and 4 boys in 1 day
=
Hence work will be over in
Incorrect
…… (i)
Substituting in (i)
We get
Work done by 20 men and 4 boys in 1 day
=
Hence work will be over in

Question 67 of 150
67. Question
1 pointsA takes half as long to do a piece of work as B takes and if C does it in same time as A and B together, and if all three working together will take 7 days to complete the work then B working alone would finish the job in
Correct
x = 42
time = 42 days
Incorrect
x = 42
time = 42 days

Question 68 of 150
68. Question
1 pointsA can do as much work in 3 days as C in 4 days and B can do as much work in 5 days as C in 6 days. Time needed by B to finish a work which A can finish in 18 days is
Correct
But
b needs 20 days to finish the work
Incorrect
But
b needs 20 days to finish the work

Question 69 of 150
69. Question
1 pointsA can finish a job in 15 days and B can do it in 10 days. If they work together then A’s share out of total wages of Rs. 2250 is
Correct
A : B =
A’ share =
Incorrect
A : B =
A’ share =

Question 70 of 150
70. Question
1 pointsA can do a piece of work in 8 days and B can do the same work in 12 days. A and B together Complete the job and get Rs. 200 as combined wages. B’s share in the wage will be
Correct
A:B =
B’s share =
Incorrect
A:B =
B’s share =

Question 71 of 150
71. Question
1 pointsTwo men A and B working together completed a piece of work which would have taken them respectively 12 and 18 days to complete if they had worked separately. They received a payment of Rs. 29,850. Then share of A is
Correct
A : B =
A’ share =
Incorrect
A : B =
A’ share =

Question 72 of 150
72. Question
1 pointsA, B and C together do a piece of work for Rs. 5350. A working alone could do it in 5 days, B in 6 days and C in 7 days. The share of C is
Correct
A : B : C =
C’s share =
Incorrect
A : B : C =
C’s share =

Question 73 of 150
73. Question
1 pointsWages of 45 women amount to Rs. 93150 in 48 days, Daily wage of a man is twice that of a women. The number of men who in 16 days will earn Rs. 34500
Correct
Wages of women days = 93150
Wages of 1 woman day =
Wage of 1 man day =
n = 25
Incorrect
Wages of women days = 93150
Wages of 1 woman day =
Wage of 1 man day =
n = 25

Question 74 of 150
74. Question
1 pointsA Field can be reaped by 10 women in 4 days or by 6 boys in 10 days or by 2 men in 12 days. 1 man, 3 boys and 2 women are employed. If the daily wages of a man, a woman and a child are Rs. 153, Rs. 93 and Rs. 57 respectively then the total expense of reaping the field is
Correct
=
Work will be over in
Wages =
= Rs.3600
Incorrect
=
Work will be over in
Wages =
= Rs.3600

Question 75 of 150
75. Question
1 points4 men earn as much in a day as 7 women; and 1 woman earns as much in a day as 2 boys. If 6 men, 10 women and 14 boys working together for 8 days earn Rs. 9900 then 8 men and 6 women working together for 10 days will earn
Correct
Incorrect

Question 76 of 150
76. Question
1 pointsThe distance between two stations A and B is 300 km. A train leaves the station A with a speed of 40 km/hr. At the same time another train depart from the station B with a speed of 50 km/h. The time after which these two trains to meet each other is
Correct
Relative speed = 40 + 50 90 km/hr
Distance = 300 km
Time = = 3 hrs 20 minutes.
Incorrect
Relative speed = 40 + 50 90 km/hr
Distance = 300 km
Time = = 3 hrs 20 minutes.

Question 77 of 150
77. Question
1 pointsA passenger train takes two hours less for a journey of 300 km if its speed is increased by 5 km/hr from its normal speed. The normal speed is
Correct
Let the normal speed by x km/hr
Then, Solving x = 25
Incorrect
Let the normal speed by x km/hr
Then, Solving x = 25

Question 78 of 150
78. Question
1 pointsThe speed of a metro train is 54 km/hr excluding stoppage time and if including stoppage, the speed is 45 km/hr, then for how many minutes does it stop per hour?
Correct
Stoppage time is the time taken to cover a distance of (5445) km at the speed of 54 km/h
54 Km : 60 min = 9 km : x min
Solving x = 10
Incorrect
Stoppage time is the time taken to cover a distance of (5445) km at the speed of 54 km/h
54 Km : 60 min = 9 km : x min
Solving x = 10

Question 79 of 150
79. Question
1 pointsAn express train runs an average speed 100 kmph stopping 3 minutes after 75 km. A local train runs at a speed of 50 kmph, stopping for 1 minute after every 25 km. If the train began running at the same time, how many kilometers did the local train run in the time it took the express train to run 600 km?
Correct
For express train : time to run 600 km = 6hrs. But this also includes 7 stoppages of 3 minutes each. Hence total time = 6 hrs 21 minutes or (381 minutes)
The local train covers 25 km in every 31 minutes.
This mean train has covered
still 9 minutes are left.
The train covers another
Hence total distance travelled = 307.5 km.
Incorrect
For express train : time to run 600 km = 6hrs. But this also includes 7 stoppages of 3 minutes each. Hence total time = 6 hrs 21 minutes or (381 minutes)
The local train covers 25 km in every 31 minutes.
This mean train has covered
still 9 minutes are left.
The train covers another
Hence total distance travelled = 307.5 km.

Question 80 of 150
80. Question
1 pointsExcluding stoppages, the speed of a bus is 54 km/h and including stoppages, it is 36 km/h. The stoppage time of the bus in minutes is
Correct
Had the bus not stopped it would have covered 18 km more in one hour. So stoppage time is the time needed to cover 18 km at the speed of 54 km/hr
54 km : 60 min = 18 km : x min
X= 20
Incorrect
Had the bus not stopped it would have covered 18 km more in one hour. So stoppage time is the time needed to cover 18 km at the speed of 54 km/hr
54 km : 60 min = 18 km : x min
X= 20

Question 81 of 150
81. Question
1 pointsAn insect climbs up a 10 metre high pole. It climbs up 3 metres in the first minute but step down 2 metres in the second minute again climbs up 3 metres in the third minute and step down 2 metres in the fourth minute and so on. It reaches the top of the pole in
Correct
The insect ascends (32) m or 1 min ever two minutes.
To ascend 7 m the insect needs 14 minutes.
Now in the fifteenth minute he ascends 3 m and reaches the top of the pole.Incorrect
The insect ascends (32) m or 1 min ever two minutes.
To ascend 7 m the insect needs 14 minutes.
Now in the fifteenth minute he ascends 3 m and reaches the top of the pole. 
Question 82 of 150
82. Question
1 pointsIf a man travels at 30 km/hr, then the reaches his destination late by 10 minutes and if he travels at 42 km/hr, then he reaches 10 minutes earlier. Therefore the distance travelled by him is
Correct
Let the distance be x km and the required time be t hrs
Then,
And
Incorrect
Let the distance be x km and the required time be t hrs
Then,
And

Question 83 of 150
83. Question
1 pointsWhich of the following trains is the fastest?
Correct
All options (a), (b) and (c) have equal value. Hence option (d) is correct.
Incorrect
All options (a), (b) and (c) have equal value. Hence option (d) is correct.

Question 84 of 150
84. Question
1 pointsA Speed of metres/second is the same as
Correct
=
= 120 km/hr.
Incorrect
=
= 120 km/hr.

Question 85 of 150
85. Question
1 pointsA and B are 25 km apart. If they travel in opposite directions, they meet an hour. If they travel in the same direction, they meet after 5 hours. If A travel faster than B, then the speed of A is
Correct
Let speeds of A and B be x km/hr and y km/hr respectively.
Then, x +y =
And x – y =
Solving: x = 15
Speed of A is 15 km/hr
Incorrect
Let speeds of A and B be x km/hr and y km/hr respectively.
Then, x +y =
And x – y =
Solving: x = 15
Speed of A is 15 km/hr

Question 86 of 150
86. Question
1 pointsA specific distance (x km) is to be covered in a specific time. If a car runs at a speed of 20 km per hour, then it reaches late by 15 minutes. If its speed is 40 km per hour, then it reaches 15 minutes earlier. The value of x would be
Correct
X = 20
Incorrect
X = 20

Question 87 of 150
87. Question
1 pointsA twice as fast as B and B is thrice as fast as C is. The journey covered by C in 42 minutes will be covered by A in
Correct
Time for C = 42 min
Time for B = = 14 min
Time for A = = 7 min
Incorrect
Time for C = 42 min
Time for B = = 14 min
Time for A = = 7 min

Question 88 of 150
88. Question
1 points38 When two trains were running in the same direction at 90 km/hr and 70 km/hr respectively, then the faster train passed a man sitting in the slower train in 36 seconds. Find the length of faster train.
Correct
Relative speed = (90 – 70) km/hr = 20 km/hr
=
=
Time = 36 seconds
= 200 m
Incorrect
Relative speed = (90 – 70) km/hr = 20 km/hr
=
=
Time = 36 seconds
= 200 m

Question 89 of 150
89. Question
1 pointsTwo trains, each 120 metres in lengths, run in opposite directions with velocities of 40 m/sec. and 20 m/sec. respectively. How long will it take for the tail end of two trains to meet each other from the time their engines crossed each other?
Correct
Distance = (120 + 120) m
= 240 m
Relative speed = (40 + 20) km/hr = 60 km/hr
=
Time = sec = 14.4 sec
Incorrect
Distance = (120 + 120) m
= 240 m
Relative speed = (40 + 20) km/hr = 60 km/hr
=
Time = sec = 14.4 sec

Question 90 of 150
90. Question
1 pointsA train speeds past a pole in 15 seconds and speeds past a platform of 100 metres long in 30 seconds. Its length (in metres) is
Correct
Let the length of the train be x m and its speed be s m/sec.
Then (we assume the horizontal length of the pole to be o m)
And
Solving x =100
Length of train is 100 m
Incorrect
Let the length of the train be x m and its speed be s m/sec.
Then (we assume the horizontal length of the pole to be o m)
And
Solving x =100
Length of train is 100 m

Question 91 of 150
91. Question
1 pointsA train running at the speed of 54 km/hr completely crosses a platform in 20 seconds. If the platforms is 100 m long the length of the train in metres is
Correct
54 km/hr =
Time = 20 sec
Let length of the train be x, then 100 + x =
So length of the train is = 200 m
Incorrect
54 km/hr =
Time = 20 sec
Let length of the train be x, then 100 + x =
So length of the train is = 200 m

Question 92 of 150
92. Question
1 pointsA train 120 m long completely crosses a platform 55 m long in 10 seconds. Speed of the train in km/h is
Correct
Speed = = 17.5 m/s = 63 km/hr
Incorrect
Speed = = 17.5 m/s = 63 km/hr

Question 93 of 150
93. Question
1 pointsTwo trains 101 m and 99 m long are running in opposite directions along parallel tracks at the speeds of 40 km/hr and 32 km/hr. The time taken by them is completely clear of each other in seconds is
Correct
Relative speed 40 + 32 = 72 km/hr =
Sum of lengths = 200 m so time =
Incorrect
Relative speed 40 + 32 = 72 km/hr =
Sum of lengths = 200 m so time =

Question 94 of 150
94. Question
1 pointsTwo trains are running in opposite directions along parallel tracks at the speeds of 50 km/hr and 40 km/hr take 8 seconds to completely clear off each other. If the faster train is 125 m long, the length of the shorter train in metres is
Correct
Relative speed = 50 + 40 = 90 km/hr =
Let length of the first train be x m, then (125 + x) =
Hence length of the first train = 75 m
Incorrect
Relative speed = 50 + 40 = 90 km/hr =
Let length of the first train be x m, then (125 + x) =
Hence length of the first train = 75 m

Question 95 of 150
95. Question
1 pointsTwo trains 120 m and 160 m long running in opposite direction along parallel tracks took 8 seconds to completely clear off each other. If the speed of one of the trains is 70 km/hr then the speed of the other train in km/hr is
Correct
Sum of lengths = 280 m
Time = 8 seconds
Relative speed = = 35 m/s = 126 km/hr
70 + x = 136
Or x = 56 km/hr
Incorrect
Sum of lengths = 280 m
Time = 8 seconds
Relative speed = = 35 m/s = 126 km/hr
70 + x = 136
Or x = 56 km/hr

Question 96 of 150
96. Question
1 pointsA steamer goes downstream and covers the distance between two towns in 20 hours. Coming back upstream it takes 5 hours more to do so. If speed of water is 4 km/hr, the distance between the two towns is
Correct
Distance downstream = distance upstream
x = 36
Distance = 800 km
Incorrect
Distance downstream = distance upstream
x = 36
Distance = 800 km

Question 97 of 150
97. Question
1 pointsA race boat covers 33 km downstream in 55 minutes. To come back to the starting point it takes one hour. Speed of boat in still water is
Correct
Speed of downstream = km/min = 36 km/hr
Speed upstream = 33 km/hr
Speed of boat in still water = km/hr = 34.5 km/hr
Incorrect
Speed of downstream = km/min = 36 km/hr
Speed upstream = 33 km/hr
Speed of boat in still water = km/hr = 34.5 km/hr

Question 98 of 150
98. Question
1 pointsIn one hour a boat goes 11 km along the stream or 5 km against the stream. The speed of the boat in still water (in km/hr) is
Correct
Let speed of boat in still water b x km/hr speed of stream by y km/hr.
Then x + y = 11
And x – y = 5
Solving x = 8
Hence speed of boat in still water = 8 km/hr
Incorrect
Let speed of boat in still water b x km/hr speed of stream by y km/hr.
Then x + y = 11
And x – y = 5
Solving x = 8
Hence speed of boat in still water = 8 km/hr

Question 99 of 150
99. Question
1 pointsA boat goes 8 km in one hour along the stream and 2 km in one hour against the stream. The speed of the steam (in km/hr) is
Correct
Let speed of boat in still water be x km/hr and speed of stream by y km/hr
Then x + y = 8
And x – y =2
Solving y = 3
Hence speed of stream = 3 km/hr.
Incorrect
Let speed of boat in still water be x km/hr and speed of stream by y km/hr
Then x + y = 8
And x – y =2
Solving y = 3
Hence speed of stream = 3 km/hr.

Question 100 of 150
100. Question
1 pointsA boat goes 6 km an hour in still water, but it takes thrice as much time in going the same distance against the current. The speed of the current (in km/hr) is
Correct
Let speed of boat in still water = 6 km/hr
Let speed of stream be x km/hr
Time upstream =
6 – x =
x = 3
Hence speed of current is 3 km/hr.
Incorrect
Let speed of boat in still water = 6 km/hr
Let speed of stream be x km/hr
Time upstream =
6 – x =
x = 3
Hence speed of current is 3 km/hr.

Question 101 of 150
101. Question
1 pointsIf x = 2 then the value of is
Correct
Let = y
(y – 4) (y – 1) = 0
Y = 1, 4
Incorrect
Let = y
(y – 4) (y – 1) = 0
Y = 1, 4

Question 102 of 150
102. Question
1 pointsx + y = p and xy = q, then the value of will be
Correct
Use
So,
=
=
=
=
Incorrect
Use
So,
=
=
=
=

Question 103 of 150
103. Question
1 pointsx + y = 5 and xy = 6, then the value of will be
Correct
=
=
Incorrect
=
=

Question 104 of 150
104. Question
1 pointsIf x = 2, then value of
Correct
Let
Incorrect
Let

Question 105 of 150
105. Question
1 pointsIf then the value of xyz will be
Correct
Incorrect

Question 106 of 150
106. Question
1 pointsIf then value of x will be
Correct
X + y = 2
X – 2y = 3
Put y = 2 – x
x – 2(2 – x) = 3
Incorrect
X + y = 2
X – 2y = 3
Put y = 2 – x
x – 2(2 – x) = 3

Question 107 of 150
107. Question
1 pointsThe difference of is
Correct
Difference =
=
=
Incorrect
Difference =
=
=

Question 108 of 150
108. Question
1 pointsIf then x will be
Correct
Incorrect

Question 109 of 150
109. Question
1 pointsIf f(y) = will be
Correct
=
Incorrect
=

Question 110 of 150
110. Question
1 pointsIf then y is equal to
Correct
X + 2y = 2x + 5y
x = 3
Y =
Incorrect
X + 2y = 2x + 5y
x = 3
Y =

Question 111 of 150
111. Question
1 pointsFactors of
Correct
=
= 2y(y – 4) – 1(y – 4)
= (2y – 1) (y – 4)
Incorrect
=
= 2y(y – 4) – 1(y – 4)
= (2y – 1) (y – 4)

Question 112 of 150
112. Question
1 pointsIf is
Correct
X + y = 5
X  y = 4
2x = 9
So
Incorrect
X + y = 5
X  y = 4
2x = 9
So

Question 113 of 150
113. Question
1 pointsIf is equal to
Correct
Incorrect

Question 114 of 150
114. Question
1 pointsIf x + y =12 and xy = 32, then =?
Correct
x + y = 12, xy = 32
(x – 8) (x – 4) = 0
x = 4, 8
y = 8, 4
=
Incorrect
x + y = 12, xy = 32
(x – 8) (x – 4) = 0
x = 4, 8
y = 8, 4
=

Question 115 of 150
115. Question
1 pointsis equal to
Correct
N = 8
Incorrect
N = 8

Question 116 of 150
116. Question
1 pointsA quadratic polynomial, whose zeroes and 5 and 8 is
Correct
=
Incorrect
=

Question 117 of 150
117. Question
1 pointsThe number of polynomial having zeroes 1 and 2 is
Correct
Incorrect

Question 118 of 150
118. Question
1 pointsGiven that one of the zeroes of the cubic polynomial is zero, the product of the under two zeroes is
Correct
Where
Incorrect
Where

Question 119 of 150
119. Question
1 pointsGiven that two of the zeroes of the cubic polynomial are 0, the value of c is
Correct
c = 0
Incorrect
c = 0

Question 120 of 150
120. Question
1 pointsIf the zeroes of the quadratic polynomial are equal, then
Correct
Zeroes are equal
polynomial is perfect square
c and a have the same sign
Incorrect
Zeroes are equal
polynomial is perfect square
c and a have the same sign

Question 121 of 150
121. Question
1 pointsThe zeroes of the quadratic polynomial
Correct
Incorrect

Question 122 of 150
122. Question
1 pointsThe zeroes of the quadratic polynomial are
Correct
Incorrect

Question 123 of 150
123. Question
1 pointsWhich of the following is a polynomial?
Correct
Incorrect

Question 124 of 150
124. Question
1 pointsIf (x + 1) is a factor of polynomial then the value of k is
Correct
Put x =1,
Incorrect
Put x =1,

Question 125 of 150
125. Question
1 pointsZero of the polynomial p(x) = 2x + 5 is
Correct
2x + 5 = 0
Incorrect
2x + 5 = 0

Question 126 of 150
126. Question
1 pointsIf is divided by (x + 1), the remainder is
Correct
Put x = 1
= 0
Incorrect
Put x = 1
= 0

Question 127 of 150
127. Question
1 points(x + 1) is a factor of the polynomial
Correct
Put x = 1
We get the value of polynomial is 0 so (x + 1) is a factor of (b)
Incorrect
Put x = 1
We get the value of polynomial is 0 so (x + 1) is a factor of (b)

Question 128 of 150
128. Question
1 pointsWhich of the following shows factor of
Correct
=
=
=
Incorrect
=
=
=

Question 129 of 150
129. Question
1 pointsOne of the factors of is
Correct
= (5x + 1) (5x + 1) +
= (5x + 1) (5x 1 + 5x + 1)
= (5x + 1) (10x)
Incorrect
= (5x + 1) (5x + 1) +
= (5x + 1) (5x 1 + 5x + 1)
= (5x + 1) (10x)

Question 130 of 150
130. Question
1 pointsThe value of
Correct
= (249 – 248) (249 + 248)
= 1 (497)
= 497
Incorrect
= (249 – 248) (249 + 248)
= 1 (497)
= 497

Question 131 of 150
131. Question
1 pointsIf is
Correct
= 0
Incorrect
= 0

Question 132 of 150
132. Question
1 pointsIf , then the value of b is
Correct
Incorrect

Question 133 of 150
133. Question
1 pointsWhich of the following is a factor of
Correct
=
= 3xy(x + y)
Incorrect
=
= 3xy(x + y)

Question 134 of 150
134. Question
1 pointsIf a + b + c = 0, then is equal to
Correct
= (a + b + c)
=
=
Incorrect
= (a + b + c)
=
=

Question 135 of 150
135. Question
1 pointsWhich of the following is a quadratic polynomial in one variable?
Correct
Incorrect

Question 136 of 150
136. Question
1 pointsDegree of which of the following polynomial is zero ?
Correct
Incorrect

Question 137 of 150
137. Question
1 pointsZero of the polynomial p(x) where p(x) =ax, a ≠ 0 is
Correct
Incorrect

Question 138 of 150
138. Question
1 pointsWhat is the remainder when is divided b (x – 1)?
Correct
Putting x = 1
We get
Incorrect
Putting x = 1
We get

Question 139 of 150
139. Question
1 pointsIf 1 is zero of the polynomial then value of p is
Correct
Put x = 1
P + 2 – 2 = 0
P = 0
Incorrect
Put x = 1
P + 2 – 2 = 0
P = 0

Question 140 of 150
140. Question
1 pointsIf p(x) = (x – a) w(x) + p(a) and (x – a) is a factor of p(x), then p(a) is
Correct
Incorrect

Question 141 of 150
141. Question
1 pointsIf p(x) = then p(x – 1) is
Correct
p( 1) =
=
=
Incorrect
p( 1) =
=
=

Question 142 of 150
142. Question
1 pointsFactors of are
Correct
=
= 4x (3x – 1) 1(3x – 1)
= (4x – 1) (3x – 1)
Incorrect
=
= 4x (3x – 1) 1(3x – 1)
= (4x – 1) (3x – 1)

Question 143 of 150
143. Question
1 pointsIf 2x + 3y = 8 and xy = 4 then value of is
Correct
Incorrect

Question 144 of 150
144. Question
1 pointsIf and xy = 4 then value of 3x + y is
Correct
= 31 + 18
3x + y =7
Incorrect
= 31 + 18
3x + y =7

Question 145 of 150
145. Question
1 pointsIf is
Correct
= 38 2
Incorrect
= 38 2

Question 146 of 150
146. Question
1 pointsProduct of (3x + 2y) (3x – 2y) is
Correct
(3x + 2y) (3x – 2y)
=
=
Incorrect
(3x + 2y) (3x – 2y)
=
=

Question 147 of 150
147. Question
1 pointsProduct of
is
Correct
=
=
Incorrect
=
=

Question 148 of 150
148. Question
1 pointsFactors of are
Correct
= 3x (x – 1) + 4 (x 1)
= 3 (x – 1) (3x + 4)
Incorrect
= 3x (x – 1) + 4 (x 1)
= 3 (x – 1) (3x + 4)

Question 149 of 150
149. Question
1 pointsIf x = then the value of a is
Correct
p(x) =
=
a = 12
Incorrect
p(x) =
=
a = 12

Question 150 of 150
150. Question
1 pointsIf and a + b + c = 10 then value of ab + bc + ca is
Correct
= 30 + 2 (ab + bc + ca)
= ab + bc + ca = 35
Incorrect
= 30 + 2 (ab + bc + ca)
= ab + bc + ca = 35
0 Comments